📝 فرض تأليفي عدد 2 في الرياضيات 📝

$f = -(-8) - |\frac{5}{2}| + 1$
$f = 8 - 2,5 + 1$
$f = 5,5 + 1 = 6,5$ ✅

$d = (-\frac{3}{5} - \frac{15}{5}) - |\frac{5}{2}|$
$d = -\frac{18}{5} - \frac{5}{2}$
$d = -3,6 - 2,5 = -6,1$ ✅

$I = [\frac{3}{4} + (a + \frac{1}{3})] - (b - 1)$
$I = \frac{3}{4} + a + \frac{1}{3} - b + 1$
$I = a - b + (\frac{9}{12} + \frac{4}{12} + \frac{12}{12})$
$I = a - b + \frac{25}{12}$ ✅

$I = -\frac{1}{2} + \frac{25}{12} = -\frac{6}{12} + \frac{25}{12}$
$I = \frac{19}{12}$ ✅

$a - b + \frac{25}{12} = -1$
$a - b = -1 - \frac{25}{12} = -\frac{12}{12} - \frac{25}{12}$
$a - b = -\frac{37}{12}$ ✅

$E = [-x + \frac{1}{2} + y - y + \frac{3}{5}] - [0,1 - x + y + x + \frac{3}{4}]$
$E = [-x + 0,5 + 0,6] - [0,1 + y + 0,75]$
$E = -x + 1,1 - 0,1 - y - 0,75$
$E = -x - y + (1 - 0,75)$
$E = 0,25 - x - y = \frac{1}{4} - x - y$ ✅

$E = \frac{1}{4} - (x + y) = \frac{1}{4} - 0$
$E = \frac{1}{4}$ ✅

$(a + \frac{3}{2}) - (-b + \frac{5}{4}) = a + \frac{3}{2} + b - \frac{5}{4}$
$= (a + b) + (\frac{6}{4} - \frac{5}{4}) = -1 + \frac{1}{4} = -0,75$

$(-b - \frac{1}{5}) - (-a + 1) = -b - \frac{1}{5} + a - 1$
$= (a - b) - \frac{1}{5} - \frac{5}{5} = -\frac{1}{2} - \frac{6}{5}$
$= -0,5 - 1,2 = -1,7$