1نلاحظ أن 2x + √2 = √2(√2x + 1)
\[2x + \sqrt{2} = \sqrt{2}(\sqrt{2}x + 1)\]
2وكذلك √2·x + 1 = 1·(√2x + 1)
\[\sqrt{2}\,x + 1 = 1 \cdot (\sqrt{2}x + 1)\]
3نستخرج العامل المشترك (√2x + 1)
\[B = \sqrt{2}(\sqrt{2}x+1)(x-1) + 1\cdot(\sqrt{2}x+1)\]
4نضع بين قوسين
\[B = (\sqrt{2}x+1)\left[\sqrt{2}(x-1) + 1\right]\]
5نبسّط
\[B = (\sqrt{2}x+1)(\sqrt{2}x - \sqrt{2} + 1)\]
6الإجابة النهائية
\[B = (\sqrt{2}x + 1)(\sqrt{2}x - \sqrt{2} + 1)\]
الجواب النهائي :\[B = (\sqrt{2}x + 1)(\sqrt{2}x - \sqrt{2} + 1)\]