ضرب الكسور — السنة الرابعة إعدادي

📐 الكسور التمرين 6 تمرين 6 من 6
6
أحسب وأعطِ النتيجة في صورة كسر مبسَّط :
\(A=\dfrac{1}{9}\times\dfrac{5}{2}\)
\(B=\dfrac{1}{2}\times\dfrac{4}{7}\)
\(C=\dfrac{1}{2}\times\dfrac{-7}{8}\)
\(D=\dfrac{-7}{5}\times\dfrac{-3}{-8}\)
\(E=\dfrac{70}{81}\times\dfrac{45}{28}\)
\(F=\dfrac{27}{70}\times\dfrac{6}{35}\)
\(G=\dfrac{-80}{12}\times\dfrac{24}{-21}\)
\(H=\dfrac{-48}{-10}\times\dfrac{-35}{-56}\)
لم تبدأ بعد

💡 الخطوة 1 — تبسيط قبل الضرب

\(\text{لا تبسيط}\)
\(\dfrac{1}{\cancelto{1}{2}}\times\dfrac{\cancelto{2}{4}}{7}\)
\(\text{لا تبسيط}\)
\(\text{لا تبسيط}\)
\(\dfrac{\cancelto{5}{70}}{\cancelto{9}{81}}\times\dfrac{\cancelto{5}{45}}{\cancelto{2}{28}}\)
\(\dfrac{27}{\cancelto{35}{70}}\times\dfrac{\cancelto{3}{6}}{35}\)
\(\dfrac{-80}{\cancelto{1}{12}}\times\dfrac{\cancelto{2}{24}}{-21}\)
\(\dfrac{\cancelto{-6}{-48}}{\cancelto{-2}{-10}}\times\dfrac{\cancelto{-7}{-35}}{\cancelto{-7}{-56}}\)

📝 الخطوة 2 — ضرب الأعداد المبسطة

\(\dfrac{1}{9}\times\dfrac{5}{2}=\dfrac{5}{18}\)
\(\dfrac{1}{1}\times\dfrac{2}{7}=\dfrac{2}{7}\)
\(\dfrac{1}{2}\times\dfrac{-7}{8}=\dfrac{-7}{16}\)
\(\dfrac{-7}{5}\times\dfrac{-3}{-8}=\dfrac{21}{-40}\)
\(\dfrac{5}{9}\times\dfrac{5}{2}=\dfrac{25}{18}\)
\(\dfrac{27}{35}\times\dfrac{3}{35}=\dfrac{81}{1225}\)
\(\dfrac{-80}{1}\times\dfrac{2}{-21}=\dfrac{-160}{-21}\)
\(\dfrac{-6}{-2}\times\dfrac{-7}{-7}=\dfrac{42}{14}\)

✅ النتيجة النهائية

\(\dfrac{5}{18}\)
\(\dfrac{2}{7}\)
\(\dfrac{-7}{16}\)
\(\dfrac{-21}{40}\)
\(\dfrac{25}{18}\)
\(\dfrac{81}{1225}\)
\(\dfrac{160}{21}\)
\(3\)