ضرب الكسور — السنة الرابعة إعدادي

📐 الكسور التمرين 1 تمرين 1 من 6
1
أحسب وأعطِ النتيجة في صورة كسر مبسَّط :
\(A=\dfrac{7}{8}\times\dfrac{1}{7}\)
\(B=\dfrac{5}{2}\times\dfrac{5}{8}\)
\(C=\dfrac{-7}{2}\times\dfrac{2}{-9}\)
\(D=\dfrac{-9}{2}\times\dfrac{-5}{2}\)
\(E=\dfrac{27}{10}\times\dfrac{27}{50}\)
\(F=\dfrac{5}{54}\times\dfrac{63}{10}\)
\(G=\dfrac{-18}{-40}\times\dfrac{5}{18}\)
\(H=\dfrac{-2}{45}\times\dfrac{6}{-27}\)
لم تبدأ بعد

💡 الخطوة 1 — تبسيط قبل الضرب

\(\dfrac{\cancelto{1}{7}}{8}\times\dfrac{1}{\cancelto{1}{7}}\)
\(\text{لا تبسيط}\)
\(\dfrac{-7}{\cancelto{1}{2}}\times\dfrac{\cancelto{1}{2}}{-9}\)
\(\text{لا تبسيط}\)
\(\text{لا تبسيط}\)
\(\dfrac{\cancelto{1}{5}}{\cancelto{6}{54}}\times\dfrac{\cancelto{7}{63}}{\cancelto{2}{10}}\)
\(\dfrac{\cancelto{-1}{-18}}{\cancelto{-8}{-40}}\times\dfrac{\cancelto{1}{5}}{\cancelto{1}{18}}\)
\(\dfrac{-2}{\cancelto{15}{45}}\times\dfrac{\cancelto{2}{6}}{-27}\)

📝 الخطوة 2 — ضرب الأعداد المبسطة

\(\dfrac{1}{8}\times\dfrac{1}{1}=\dfrac{1}{8}\)
\(\dfrac{5}{2}\times\dfrac{5}{8}=\dfrac{25}{16}\)
\(\dfrac{-7}{1}\times\dfrac{1}{-9}=\dfrac{-7}{-9}\)
\(\dfrac{-9}{2}\times\dfrac{-5}{2}=\dfrac{45}{4}\)
\(\dfrac{27}{10}\times\dfrac{27}{50}=\dfrac{729}{500}\)
\(\dfrac{1}{6}\times\dfrac{7}{2}=\dfrac{7}{12}\)
\(\dfrac{-1}{-8}\times\dfrac{1}{1}=\dfrac{-1}{-8}\)
\(\dfrac{-2}{15}\times\dfrac{2}{-27}=\dfrac{-4}{-405}\)

✅ النتيجة النهائية

\(\dfrac{1}{8}\)
\(\dfrac{25}{16}\)
\(\dfrac{7}{9}\)
\(\dfrac{45}{4}\)
\(\dfrac{729}{500}\)
\(\dfrac{7}{12}\)
\(\dfrac{1}{8}\)
\(\dfrac{4}{405}\)