إيجاد x (جمع)أوجد قيمة x :
\( x+\dfrac{2}{6}=\dfrac{4}{9} \)
✅ التصحيح
من x+a=b نستنتج x=b−a
\( x+\dfrac{2}{6}=\dfrac{4}{9} x=\dfrac{4}{9}-\dfrac{2}{6}=\dfrac{1}{9} \)
إيجاد x (طرح)أوجد قيمة x :
\( \dfrac{17}{20}-x=\dfrac{3}{5} \)
✅ التصحيح
من a−x=b نستنتج x=a−b
\( \dfrac{17}{20}-x=\dfrac{3}{5} x=\dfrac{17}{20}-\dfrac{3}{5}=\dfrac{2}{8} \)
الصيغة 2أاحسب :
\( \dfrac{4}{3}+\left(\dfrac{2}{3}-\dfrac{2}{6}\right) \)
✅ التصحيح
بتطبيق: a+(b±c) = (a+b)±c حيث a+b=2 ∈ ℕ
\( \dfrac{4}{3}+\left(\dfrac{2}{3}-\dfrac{2}{6}\right) =\left(\dfrac{4}{3}+\dfrac{2}{3}\right)-\dfrac{2}{6} = 2-\dfrac{2}{6} = \dfrac{5}{3} \)
الصيغة 2أاحسب :
\( \dfrac{26}{7}+\left(\dfrac{2}{7}+\dfrac{3}{7}\right) \)
✅ التصحيح
بتطبيق: a+(b±c) = (a+b)±c حيث a+b=4 ∈ ℕ
\( \dfrac{26}{7}+\left(\dfrac{2}{7}+\dfrac{3}{7}\right) =\left(\dfrac{26}{7}+\dfrac{2}{7}\right)+\dfrac{3}{7} = 4+\dfrac{3}{7} = \dfrac{31}{7} \)
الصيغة 1احسب :
\( \left(\dfrac{3}{10}+\dfrac{34}{807}\right)+\left(\dfrac{2}{7}-\dfrac{34}{807}\right) \)
✅ التصحيح
بتطبيق: (a+c)+(b-c) = a+b [c يختصر]
\( \left(\dfrac{3}{10}+\dfrac{34}{807}\right)+\left(\dfrac{2}{7}-\dfrac{34}{807}\right) = \dfrac{3}{10}+\dfrac{2}{7} = \dfrac{41}{70} \)
إيجاد x (جمع)أوجد قيمة x :
\( x-\dfrac{3}{10}=\dfrac{43}{90} \)
✅ التصحيح
من x−a=b نستنتج x=b+a
\( x-\dfrac{3}{10}=\dfrac{43}{90} x=\dfrac{43}{90}+\dfrac{3}{10}=\dfrac{7}{9} \)
الصيغة 1احسب :
\( \left(\dfrac{7}{10}-\dfrac{20}{649}\right)-\left(\dfrac{2}{10}-\dfrac{20}{649}\right) \)
✅ التصحيح
بتطبيق: (a-c)−(b-c) = a−b [c يختصر]
\( \left(\dfrac{7}{10}-\dfrac{20}{649}\right)-\left(\dfrac{2}{10}-\dfrac{20}{649}\right) = \dfrac{7}{10}-\dfrac{2}{10} = \dfrac{1}{2} \)
الصيغة 1احسب :
\( \left(\dfrac{2}{3}-\dfrac{12}{726}\right)+\left(\dfrac{6}{8}+\dfrac{12}{726}\right) \)
✅ التصحيح
بتطبيق: (a-c)+(b+c) = a+b [c يختصر]
\( \left(\dfrac{2}{3}-\dfrac{12}{726}\right)+\left(\dfrac{6}{8}+\dfrac{12}{726}\right) = \dfrac{2}{3}+\dfrac{6}{8} = \dfrac{17}{12} \)
الصيغة 2باحسب :
\( \dfrac{19}{4}-\left(\dfrac{3}{4}+\dfrac{4}{5}\right) \)
✅ التصحيح
بتطبيق: a−(b+c) = (a−b)−c حيث a−b=4 ∈ ℕ
\( \dfrac{19}{4}-\left(\dfrac{3}{4}+\dfrac{4}{5}\right) =\left(\dfrac{19}{4}-\dfrac{3}{4}\right)-\dfrac{4}{5} = 4-\dfrac{4}{5} = \dfrac{16}{5} \)
الصيغة 1احسب :
\( \left(\dfrac{2}{5}+\dfrac{45}{832}\right)+\left(\dfrac{2}{6}-\dfrac{45}{832}\right) \)
✅ التصحيح
بتطبيق: (a+c)+(b-c) = a+b [c يختصر]
\( \left(\dfrac{2}{5}+\dfrac{45}{832}\right)+\left(\dfrac{2}{6}-\dfrac{45}{832}\right) = \dfrac{2}{5}+\dfrac{2}{6} = \dfrac{11}{15} \)