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✅ التصحيح

بتطبيق: (a-c)−(b-c) = a−b [c يختصر]

\( \left(\dfrac{7}{8}-\dfrac{29}{529}\right)-\left(\dfrac{8}{11}-\dfrac{29}{529}\right) = \dfrac{7}{8}-\dfrac{8}{11} = \dfrac{13}{88} \)

✅ التصحيح

من a−x=b نستنتج x=a−b

\( \dfrac{21}{22}-x=\dfrac{5}{11} x=\dfrac{21}{22}-\dfrac{5}{11}=\dfrac{1}{2} \)

✅ التصحيح

بتطبيق: a−(b+c) = (a−b)−c حيث a−b=5 ∈ ℕ

\( \dfrac{16}{3}-\left(\dfrac{2}{6}+\dfrac{6}{8}\right) =\left(\dfrac{16}{3}-\dfrac{2}{6}\right)-\dfrac{6}{8} = 5-\dfrac{6}{8} = \dfrac{17}{4} \)

✅ التصحيح

بتطبيق: (a-c)−(b-c) = a−b [c يختصر]

\( \left(\dfrac{3}{5}-\dfrac{10}{550}\right)-\left(\dfrac{1}{10}-\dfrac{10}{550}\right) = \dfrac{3}{5}-\dfrac{1}{10} = \dfrac{1}{2} \)

✅ التصحيح

من x+a=b نستنتج x=b−a

\( x+\dfrac{4}{10}=\dfrac{4}{5} x=\dfrac{4}{5}-\dfrac{4}{10}=\dfrac{2}{5} \)

✅ التصحيح

بتطبيق: (a-c)+(b+c) = a+b [c يختصر]

\( \left(\dfrac{7}{12}-\dfrac{3}{533}\right)+\left(\dfrac{1}{2}+\dfrac{3}{533}\right) = \dfrac{7}{12}+\dfrac{1}{2} = \dfrac{13}{12} \)

✅ التصحيح

بتطبيق: (a-c)−(b-c) = a−b [c يختصر]

\( \left(\dfrac{8}{12}-\dfrac{13}{806}\right)-\left(\dfrac{4}{9}-\dfrac{13}{806}\right) = \dfrac{8}{12}-\dfrac{4}{9} = \dfrac{2}{9} \)

✅ التصحيح

بتطبيق: a+(b±c) = (a+b)±c حيث a+b=5 ∈ ℕ

\( \dfrac{13}{3}+\left(\dfrac{2}{3}-\dfrac{5}{8}\right) =\left(\dfrac{13}{3}+\dfrac{2}{3}\right)-\dfrac{5}{8} = 5-\dfrac{5}{8} = \dfrac{35}{8} \)

✅ التصحيح

بتطبيق: a+(b±c) = (a+b)±c حيث a+b=4 ∈ ℕ

\( \dfrac{24}{7}+\left(\dfrac{4}{7}+\dfrac{5}{6}\right) =\left(\dfrac{24}{7}+\dfrac{4}{7}\right)+\dfrac{5}{6} = 4+\dfrac{5}{6} = \dfrac{29}{6} \)

✅ التصحيح

من a−x=b نستنتج x=a−b

\( \dfrac{8}{15}-x=\dfrac{2}{10} x=\dfrac{8}{15}-\dfrac{2}{10}=\dfrac{1}{3} \)