الصيغ على الكسور الموجبة

✅ التصحيح

من a−x=b نستنتج x=a−b

\( \dfrac{27}{88}-x=\dfrac{2}{11} x=\dfrac{27}{88}-\dfrac{2}{11}=\dfrac{1}{8} \)

✅ التصحيح

بتطبيق: (a-c)−(b-c) = a−b [c يختصر]

\( \left(\dfrac{4}{6}-\dfrac{9}{766}\right)-\left(\dfrac{6}{12}-\dfrac{9}{766}\right) = \dfrac{4}{6}-\dfrac{6}{12} = \dfrac{1}{6} \)

✅ التصحيح

بتطبيق: (a-c)−(b-c) = a−b [c يختصر]

\( \left(\dfrac{2}{3}-\dfrac{45}{851}\right)-\left(\dfrac{1}{3}-\dfrac{45}{851}\right) = \dfrac{2}{3}-\dfrac{1}{3} = \dfrac{1}{3} \)

✅ التصحيح

بتطبيق: a+(b±c) = (a+b)±c حيث a+b=1 ∈ ℕ

\( \dfrac{1}{5}+\left(\dfrac{4}{5}+\dfrac{5}{6}\right) =\left(\dfrac{1}{5}+\dfrac{4}{5}\right)+\dfrac{5}{6} = 1+\dfrac{5}{6} = \dfrac{11}{6} \)

✅ التصحيح

من a−x=b نستنتج x=a−b

\( \dfrac{23}{18}-x=\dfrac{7}{9} x=\dfrac{23}{18}-\dfrac{7}{9}=\dfrac{1}{2} \)

✅ التصحيح

بتطبيق: (a+c)+(b-c) = a+b [c يختصر]

\( \left(\dfrac{1}{5}+\dfrac{5}{896}\right)+\left(\dfrac{8}{9}-\dfrac{5}{896}\right) = \dfrac{1}{5}+\dfrac{8}{9} = \dfrac{49}{45} \)

✅ التصحيح

بتطبيق: (a-c)+(b+c) = a+b [c يختصر]

\( \left(\dfrac{3}{12}-\dfrac{8}{697}\right)+\left(\dfrac{4}{11}+\dfrac{8}{697}\right) = \dfrac{3}{12}+\dfrac{4}{11} = \dfrac{27}{44} \)

✅ التصحيح

بتطبيق: (a-c)−(b-c) = a−b [c يختصر]

\( \left(\dfrac{4}{7}-\dfrac{18}{651}\right)-\left(\dfrac{4}{8}-\dfrac{18}{651}\right) = \dfrac{4}{7}-\dfrac{4}{8} = \dfrac{1}{14} \)

✅ التصحيح

بتطبيق: a−(b+c) = (a−b)−c حيث a−b=2 ∈ ℕ

\( \dfrac{19}{8}-\left(\dfrac{3}{8}+\dfrac{5}{9}\right) =\left(\dfrac{19}{8}-\dfrac{3}{8}\right)-\dfrac{5}{9} = 2-\dfrac{5}{9} = \dfrac{13}{9} \)

✅ التصحيح

بتطبيق: a+(b±c) = (a+b)±c حيث a+b=1 ∈ ℕ

\( \dfrac{1}{4}+\left(\dfrac{3}{4}+\dfrac{4}{8}\right) =\left(\dfrac{1}{4}+\dfrac{3}{4}\right)+\dfrac{4}{8} = 1+\dfrac{4}{8} = \dfrac{3}{2} \)