الصيغة 1احسب :
\( \left(\dfrac{3}{7}-\dfrac{48}{690}\right)+\left(\dfrac{10}{12}+\dfrac{48}{690}\right) \)
✅ التصحيح
بتطبيق: (a-c)+(b+c) = a+b [c يختصر]
\( \left(\dfrac{3}{7}-\dfrac{48}{690}\right)+\left(\dfrac{10}{12}+\dfrac{48}{690}\right) = \dfrac{3}{7}+\dfrac{10}{12} = \dfrac{53}{42} \)