الصيغة 1احسب :
\( \left(\dfrac{1}{3}-\dfrac{27}{620}\right)+\left(\dfrac{8}{10}+\dfrac{27}{620}\right) \)
✅ التصحيح
بتطبيق: (a-c)+(b+c) = a+b [c يختصر]
\( \left(\dfrac{1}{3}-\dfrac{27}{620}\right)+\left(\dfrac{8}{10}+\dfrac{27}{620}\right) = \dfrac{1}{3}+\dfrac{8}{10} = \dfrac{17}{15} \)