تمرين رقم 3

① احسب:
\[a = 3^2 \times 7 - (1^{13} + 5^0)\]
\[b = (2^3 + 5^{13}) - (2^2 + 5^{13})\]
\[c = 2^2 + 3^2 \times 4 - 2^3\]
\[a = 9 \times 7 - (1 + 1)\] \[a = 63 - 2\] \[a = 61\] \[b = (8 + 5^{13}) - (4 + 5^{13})\] \[b = (8 - 4)\] \[b = 4\] \[c = 4 + 9 \times 4 - 8\] \[c = 4 + 36 - 8\] \[c = 32\]
② أكمل الفراغات بالأرقام المناسبة لتكون المساواة صحيحة:
\[100000 \times 10^{\square} = 100^5\]
\[(9^{\square})^3 = 3^{36}\]
\[100000 = 10^5\] \[100^5 = (10^2)^5 = 10^{10}\] \[10^5 \times 10^x = 10^{10}\] \[x = 5\] \[(9^x)^3 = 3^{36}\] \[9 = 3^2\] \[(3^2)^x)^3 = 3^{36}\] \[3^{6x} = 3^{36}\] \[6x = 36\] \[x = 6\]
③ اكتب في صيغة قوة لعدد صحيح طبيعي دليلها مخالف لواحد:
\[d = 3^5 \times 9^{15} \times 27^2\]
\[e = 2^{13} \times 36^5 \times 3^{13}\]
\[f = 5^{2019} \times 3^3 - 5^{2019} \times 2\]
\[d = 3^5 \times (3^2)^{15} \times (3^3)^2\] \[d = 3^5 \times 3^{30} \times 3^6\] \[d = 3^{41}\] \[e = 2^{13} \times (6^2)^5 \times 3^{13}\] \[e = 2^{13} \times 6^{10} \times 3^{13}\] \[6^{10} = (2 \times 3)^{10} = 2^{10} \times 3^{10}\] \[e = 2^{13} \times 2^{10} \times 3^{10} \times 3^{13}\] \[e = 2^{23} \times 3^{23}\] \[f = 5^{2019} \times 3^3 - 5^{2019} \times 2\] \[f = 5^{2019} \times (27 - 2)\] \[f = 5^{2019} \times 25\] \[f = 5^{2019} \times 5^2\] \[f = 5^{2021}\]